Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

71.

xe - 1 + ex - 1xe + exdx

  • - 1elogxe +ex + C

  • - elogxe +ex + C

  • 1elogxe +ex + C

  • elogxe +ex + C


72.

If a, b and c are non-zero vectors such that a and b are not perpendicular to each other, then the vector r which is perpendicular to a and satisfying r x b = c x b  is

  • a × b × cc a

  • b × a × cb c

  • b × c × aa b

  • c × b × aac


73.

x+ sinx1 + cosxdx = ?

  • xtanx2 + C

  • xsinx2 + cosx2 +C

  • xtanx2 + secx2+ C

  • xtanx2 + secx2+ C


74.

If In = sinnxcosxdx, then In = ?

  •  - 2n - 1cosn - 1x - In - 2

  • 2n - 1cosn - 1x + In - 2

  •  - 2n + 1sinn - 1x - In - 2

  •  - 2n + 1cosn - 1x - In - 2


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75.

The differential equation corresponding to the family of circles inthe plane touching the Y-axis at the origin, is

  • dydx = y2 - x22xy

  • dydx = 2xyx2 + y2

  • dydx = x2 - y22xy

  • dydx = y2 + x22xy


76.

The triad (x, y, z) of real number such that3i^ - j^ + 2k^ = 2i^ + 3j^ - k^x + i^ - 2j^ + 2k^y +  - 2i^ + j^ - 2k^z is

  • (- 2, 5, 3)

  • (2, - 5, 3)

  • (2, 5, 3)

  • (2, 5, - 3)


77.

If the volume of the tetrahedron formed by the coterminous edges a, b and c is 4, then the volume of the parallelopiped formed by the coterminous edges a x b, b x c and c x a is

  • 576

  • 48

  • 16

  • 144


78.

The incentre of the triangle formed by the straight lines y = 3x, y = - 3x and y = 3 is  and y = 3 is

  • (0, 2)

  • (1, 2)

  • (2, 0)

  • (2, 1)


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79.

The tangents to the parabola y = 4ax from an external point P make angles θ1 and θ2, with the axis of the parabola. Such that tanθ1 + tanθ2 = b where b is constant. Then P lies on

  • y = x + b

  • y + x = b

  • y = xb

  • y = bx


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80.

The points on the straight line 3x - 4y + 1 = 0 which are at a distance of 5 units from the point (3, 2) are

  •  - 2, - 74 - 3,  - 52

  • 4, 114 - 1,  - 1

  • 1, 122, 54

  • 7, 5, - 1, - 1


D.

7, 5, - 1, - 1

d We have, line 3x - 4y - 1 = 0 and point Ax1, y1which is at 5 units distance from (3, 2) equations of line PA are

x1 - 3cosθ = y1 - 2sinθ = ± 5 x1 = 3 ± 5cosθy1 = 2 ± 5sinθSince, x1, y1 lies on the 3x - 4y -  1 = 0 33 ± 5cosθ - 42 ± 5sinθ - 1 = 0 9 ± 15cosθ - 8 +20sinθ - 1= 015cosθ - 20sinθ = 0 3cosθ = ± 4sinθtanθ =± 34cosθ = ± 45sinθ = ± 35 x1 = 3 ± 455 = 7, - 1     y1 = 2 ± 535 = 5, - 1 Coordinates are 7, 5 and  - 1, - 1


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