Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

21.

The modulus of elasticity is dimensionally equivalent to

  • strain

  • force

  • stress

  • coefficient of viscosity


22.

Radius of an air bubble at the bottom of the lake is r and it becomes 2r when the air bubble rises to the top surface of the lake. If P cm of water be the atmospheric pressure, then the depth of the lake is

  • 2P

  • 8P

  • 4P

  • 7P


23.

A manometer connected to a closed tap reads 4.5 × 105 Pa. When the tap is opened the reading of the manometer falls to 4 x 105 Pa. Then the velocity of flow of water is

  • 7 ms-1

  • 8 ms-1

  • 10 ms-1

  • 12 ms-1


24.

What is the velocity v of a metallic ball of radius r falling in a tank of liquid at the instant when its acceleration is one-half that of a freely falling body ? (The densities of metal and of liquid are ρ and σ respectively, and the viscosity of the liquid is η)

  • r2g9η ρ - 2σ

  • r2g9η 2ρ - σ

  • r2g9η ρ - σ

  • 2r2g9η ρ - σ


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25.

The value of PVT for one mole of an ideal gas is nearly equal to

  • 2 J mol-1 K-1

  • 8.3 mol-1 K-1

  • 4.2 mol-1 K-1

  • 2 cal mol-1 K-1


26.

The volume of a metal sphere increases by 0.24 % when its temperature is raised by 40°C. The coefficient of linear expansion of the metal is 

  • 2 × 10-5

  • 6 × 10-5

  • 18 × 10-5

  • 1.2 × 10-5


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27.

The temperature of equal masses of three different liquids A, B and C are 12°C, 19°C and 28°C respectively. The temperature when A and B are mixed is 16°C and when B and C are mixed is 23°C. The temperature when A and C are mixed is

  • 18.2°C

  • 22°C

  • 20.2°C

  • 24.2°C


C.

20.2°C

Ist case :msA t - tA = msB tB - tsA 16 - 12 = sB 19 - 16               4sA = 3sBIInd case : msB t - tB = msC tC - tsB 23 - 19 = sC 28 - 23                4sB = 5sC                3sB = 154 sC     4sA = 3sB = 154 sC 16sA = 12sB = 15sC = k          sA : sB : sC = 116 : 112 : 115                        sA = k16 , sC = k15 , sB = k12When Aand C are mixed,msA t - tA = msC tC - t k16 t - 12 = k15 28 - t    15t - 180 = 448 - 16t                31t = 628                t = 20.2°C


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28.

The time period of the second's hand of a watch is

  • 1 h

  • 1 s

  • 12 h

  • 1 min


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29.

A particle starts SHM from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3E4. Its displacement at that instant is

  • a2

  • a2

  • a32

  • a3


30.

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in second is

  • 12π3

  • 2π3

  • 2π3

  • 32π


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