Which functional group participates in disulphide bond formation in proteins?
Thiolactone
Thiol
Thioether
Thioester
B.
Thiol
Disulphide bond may be reduced to thiol by means of reagents, such as, NaBH4, which shows the presence of thiol group in disulphide bond formation.
In a set of reactions, acetic acid yielded a product D.
CH3COOH A B C D
The structure of D would be
A.
In the above reaction,
CH3COOH CH3OCl
Which of the following undergoes nucleophilic substitution exclusively by SN1 mechanism?
Benzyl chloride
Ethyl chloride
Chlorobenzene
lsopropyl chloride
A.
Benzyl chloride
Among all the given options, benzyl chloride undergoes SN1 mechanism.
Aliphatic SN1 reaction is carried out in two steps:
(i) carbonium (carbocation) ion is formed and its formation is based upon the stability.
Stability order of carbocation-
C6H52H2 > CH3 - H - CH3 > CH3 - H2
(ii) Nucleophile is attracted towards the carbonium ion in form of fast step to give final product.
Hence, in benzyl chloride, ethyl chloride and isopropyl chloride order of SN 1 reaction is benzyl chloride > isopropyl chloride > ethyl chloride
The chirality of the compound
R
S
Z
E
A.
R
Lowest priority atom is always away from the viewer. Priority is seen on the basis of atomic number and if atomic numbers are same then on the basis of second or third bond in above figure priority order group or atom is -Br > -Cl > -CH3 > H and in it rotation is clockwise. So it shows R-configuration.
The correct order of acid strength is
HClO < HClO2 < HClO3 < HClO4
HClO4 < HClO < HClO2 < HClO3
HClO2 < HClO3 < HClO4 < HClO
HClO4 < HClO3 < HClO2 < HClO
A.
HClO < HClO2 < HClO3 < HClO4
Correct order of acid strength is
Acid strength oxidation number
Electrolytic reduction of nitrobenzene in weakly acidic medium gives
aniline
nitrosobenzene
N-phenylhydroxylamine
p-hydroxyaniline
A.
aniline
Electrolytic reduction of nitrobenzene in weakly acidic medium gives aniline but in strongly acidic medium it gives p-aminophenol through the acid-catalysed rearrangement of the initially formed phenylhydroxylamine.
C6H5NO2 C6H5NH2
Nitrobenzene Aniline
The main reason for larger number of oxidation states exhibited by the actinides than the corresponding lanthanides, is
lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
larger atomic size of actinides than the lanthanide
more energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
greater reactive nature of the actinides than the lanthanides
A.
lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
The main reason for larger number of oxidation states exhibited by actinides than corresponding lanthanides is lesser energy difference between 5f and 6d orbitals than between 4f and 5d-orbitals.
The major organic product formed from the following reaction ... is
B.
The major organic product formed from the above given equation is
The monomer of the polymer
H2C = C(CH3)2
(CH3)2C = C(CH3)2
CH3CH = CH CH3
CH3CH = CH2
A.
H2C = C(CH3)2
The monomer of the above given polymer is
CH2 = C(CH3)2
This is because it shows cationic polymerisation.
Aniline in a set of reactions yielded a product D
The structure of the product D would be
C6H5CH2NH2
C6H5NHCH2CH3
C6H5NHOH
C6H5CH2OH
D.
C6H5CH2OH
In the above figure, product D is C6H5CH2OH.