Subject

Quantitative Aptitude

Class

SSCCGL Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

111.

If fraction numerator sec space straight theta space plus space tan space straight theta over denominator sec space straight theta space minus space tan space straight theta end fraction space equals space 5 over 3 comma then sin θ is equal to

  • 2/3

  • 3/4

  • 1/4

  • 1/3

40 Views

112.

A man standing in one corner of a square football field observes that the angle subtend by a pole in the corner just diagonally opposite to this corner is 60°. When he retires 80 m from the corner, along the same straight line, he finds the angle to be 30°. The length of the field is

  • 20 m

  • 40√2 m

  • 40 m

  • 20√2 m

45 Views

113.

If the median drawn on the base of a triangle is half its base, then the triangle will be

  • obtuse angled

  • equilateral

  • right angled

  • acute angled

33 Views

114.

The average age of 14 girls and their teacher's age is 15 yr. If the teacher's age is excluded, then the average reduces by 1. What is the teacher's age?

  • 29 yr

  • 35 yr

  • 32 yr

  • 30 yr

23 Views

Advertisement
115.

If a, b and c are non-zero, straight a space plus space 1 over straight b space equals space 1 space space space and space straight b space plus space 1 over straight c space equals space 1 then the value of abc is

  • -3

  • 1

  • -1

  • 3

29 Views

116.

The value of a machine depreciates every year at the rate of 10% on its value at the beginning of that year. If the current value of the machine is ₹ 729, then its worth 3 yr ago was

  • ₹ 947.10

  • ₹ 800

  • ₹ 1000

  • ₹ 750.87

33 Views

117.

Find the maximum number of trees which can be planted 20 m apart on the two sides of a straight road 1760 m long.

  • 174

  • 176

  • 180

  • 178

42 Views

118.

Two circles of same radius 5 cm, intersect each other at A and B. If AB = 8 cm, then the distance between the centres is

  • 10 cm

  • 4 cm

  • 6 cm

  • 8 cm

31 Views

Advertisement
Advertisement

119.

The curved surface area and the total surface area of a cylinder are in the ratio 1 : 2. If the total surface area of the right cylinder is 616 cm2, then its volume is

  • 1632 cm3

  • 1078 cm3

  • 1232 cm3

  • 1848 cm3


B.

1078 cm3

Curved surface area of cylinder:
                   equals space space space 2 πrh space cm squared
Total surface area of cylinder:
                 space equals space 2 πr left parenthesis straight h space plus space straight r right parenthesis space cm squared
Now, according to the question,
  rightwards double arrow space space space space space fraction numerator 2 πrh over denominator 2 πr left parenthesis straight h plus space straight r right parenthesis end fraction space equals space 1 half
rightwards double arrow space space space space fraction numerator straight h over denominator straight h plus straight r end fraction space equals space 1 half
rightwards double arrow space space space 2 straight h space equals space straight h space plus space straight r
rightwards double arrow space space space space straight h space equals space straight r

Now, Total surface area = 616 cm2
rightwards double arrow space space space space 2 πr left parenthesis straight h space plus space straight r right parenthesis space equals space 616
rightwards double arrow space space space space 2 πr left parenthesis straight r plus space straight r right parenthesis space equals space space 616 space space space space space space space space space space left parenthesis as space straight h space equals space straight r right parenthesis
rightwards double arrow space space space space 2 πr left parenthesis 2 straight r right parenthesis space equals space 616
rightwards double arrow space space space space space space 4 πr squared space equals space space 616
therefore space space space space space space space space space space space space space space space space space straight r space equals space square root of fraction numerator 616 over denominator 4 straight pi end fraction end root space equals space square root of fraction numerator 616 space cross times space 7 over denominator 4 space cross times space 22 end fraction end root space equals space square root of 7 space cross times space 7 end root space equals space 7 space cm

∴       Volume
                equals space πr squared straight h
equals space 22 over 7 space cross times space open parentheses 7 space cross times 7 close parentheses space cross times space 7 space equals space 1078 space cm squared

31 Views

Advertisement
120.

If a + b + c = 0, then the value of
open parentheses fraction numerator straight a space plus space straight b over denominator straight c end fraction space plus space fraction numerator straight b space plus space straight c over denominator straight a end fraction space plus space fraction numerator straight c space plus space straight a over denominator straight b end fraction close parentheses space open parentheses fraction numerator straight a space over denominator straight b space plus space straight c end fraction space plus space fraction numerator straight b space over denominator straight c space plus space straight a end fraction space plus space fraction numerator straight c space over denominator straight a space plus space straight b end fraction close parentheses is

  • 9

  • 0

  • 8

  • -3

27 Views

Advertisement