In two similar triangles ABC and MNP, if AB = 2.25 cm, MP = 4.5 cm and PN = 7.5 cm and m = m and m = m, then the length of side , (in cm) is
3.75
4.75
3.5
3.5
Given an equilateral , D, E, F are the mid-points of AB, BC and AC respectively. Then, the quadrilateral BEFD is exactly a
square
rectangle
trapezium
trapezium
D.
trapezium
As we know, triangle formed by joining the mid-points of equilateral triangle is also equilateral triangle.
Therefore, DF = BE and DF || BE
DB = EF and DB || EF
Thus, Quadrilateral BEFD is exactly a rhombus.