A body is projected with velocity 19·6 m/s in horizontal direction. After what time the horizontal and vertical component of velocity will be the same? from Physics Motion in A Plane Class 11 Manipur Board
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A body is projected with velocity 19·6 m/s in horizontal direction. After what time the horizontal and vertical component of velocity will be the same?

Given, that the body is projected in the horizontal direction. 

So, we have 

straight u subscript straight x equals 0 space space space space space space space space and space space space space space straight u subscript straight y space equals space 19.6 space straight m divided by straight s
straight a subscript straight x equals 9.8 space straight m divided by straight s squared space space space space and space space space straight a subscript straight y equals 0

Now, the horizontal component of velocity at any instant is given by, 

straight v subscript straight x equals space straight u subscript straight x space plus space straight a subscript straight x space straight t space equals space 0 plus 9.8 straight t space equals space 9.8 straight t space 

Vertical component of velocity is, 

straight v subscript straight y space equals space straight u subscript straight y plus straight a subscript straight y space straight t space equals space 19.6 space plus space 0 straight t space equals space 19.6 space 

Since, horizontal and vertical component of velocity is the same, we have

        9.8 t = 19.6

i.e.,        t = 2s 
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