Given,
Radius of Earth's orbit, r = 1.5 x 1011 m
Time period of revolution of earth around the sun is 1 year.
That is,
T = 1 year = 365 x 24 x 60 x 60 s
Therefore,
Angular velocity,
Linear velocity, v =
Mean speed of car,
We have,
Initial distance, yo = 0
Height attained after time t, y = 1000 m
Initial velocity, uy = 0 m/s
Acceleration, ay = 9.8 m/s2
Time = t
Now, using the equation of motion, we have
Therefore, 14.28 sec ia taken for the bomb to reach the ground.
The relation between time t and distance x is t=ax2 +bx where a and b are constants. The acceleration is
−2abv2
2bv3
−2av3
2av2
C.
−2av3
Two persons P and Q are standing 54 m apart on a long moving belt. Person P rolls a round stone towards a person Q with a speed of 9 m/s with respect to belt. If the belt is moving with a speed of 4 m/s in the direction from P to Q. What is the speed of the stone w.r.to an observer on a stationary platform?
Let the distance from P to Q be positive.
Given, speed of the belt, vb = +4 m/s
Speed of the stone w.r.t belt, vs = + 9 m/s
Speed of the stone w.r.t a stationary observer= vs + vb = 9+ 4 = 13 m/s