Given,
Position of the particle,
∴ Velocity,
The angle which the velocity vector makes with X-axis at any instant is,
Here,
Therefore,
So, when time is 5 seconds, the velocity vector will make an angle 450 with x-axis.
The position of a particle is given by
where t is in second and r is in meter.
(a) Find the of the particle.
(b) What is the magnitude and direction of velocity of the particle at t = 2s?
(a)
Given,
Position of the particle,
∴
Velocity,
and,
Acceleration,
(b) Now,
Velocity,
At time = 2 sec,
∴
and
At t = 2 sec,
Acceleration,
∴ and directed towards negative direction of X-axis.