What is the formula to find out the radius of curvature of a spherical surface?

Radius of curvature of a spherical surface is given by, 

                            straight R space equals space fraction numerator straight l squared over denominator 6 straight h end fraction plus straight h over 2 

where,

l is average distance between the three fixed legs of spherometer, and 

h is the height of the central screw above the plane surface. 

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Compute the error in An, if percentage error in the measurement of A is α%.

Here, X =A

Let ∆A and ∆X be the absolute errors in A and X respectively.

Therefore the above equation with error can be written as




space space space space space space space space space space space space space space space space space space open parentheses straight X plus-or-minus ΔX close parentheses equals open parentheses straight A plus-or-minus ΔA close parentheses to the power of straight N
rightwards double arrow space space space space space space straight X open parentheses 1 plus-or-minus ΔX over straight X close parentheses equals straight A to the power of straight n open parentheses 1 plus-or-minus ΔA over straight A close parentheses to the power of straight n

rightwards double arrow space space space space space open parentheses 1 plus-or-minus ΔX over straight X close parentheses equals space space open parentheses 1 plus-or-minus straight n space ΔX over straight X close parentheses

rightwards double arrow space space space space space space space ΔX over straight X equals straight n ΔA over straight A 

Multiplying both sides by 100, 

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#6 {main}</pre> 

i.e. Maximum possible %age error in X = n (Maximum possible %age error in A)

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Discuss the process of combination of errors when two physical quantities are multiplied.

Let X = AB
Let ∆A, ∆B and ∆X be the absolute errors in A, B and X respectively. Therefore the above equation with error can be written as

    
space space space space space space space space space space space space space space space space straight X plus-or-minus straight capital delta equals left parenthesis straight A plus-or-minus ΔA right parenthesis left parenthesis straight B plus-or-minus ΔB right parenthesis
space space space space space space space space or space space space space space straight X open parentheses 1 plus-or-minus ΔX over straight X close parentheses equals AB open parentheses 1 plus-or-minus ΔA over straight A close parentheses open parentheses 1 plus-or-minus ΔB over straight B close parentheses
space space space space space

space space space space space space space space space space space space
space space space space space space space space space space space space space or space space space space space straight X open parentheses 1 plus-or-minus ΔX over straight X close parentheses equals AB open parentheses 1 plus-or-minus ΔA over straight A plus-or-minus ΔB over straight B plus-or-minus ΔA over straight A ΔB over straight B close parentheses
space space space space space space space space space space space space space or space space space space space space space open parentheses 1 plus-or-minus ΔX over straight X close parentheses equals open parentheses 1 plus-or-minus ΔX over straight X plus-or-minus ΔB over straight B plus-or-minus ΔA over straight A ΔB over straight B close parentheses

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#6 {main}</pre> are small quantities, theefore the product ΔA over straight A ΔB over straight B will be very small and hence can be neglected. Thus the above equation reduce to 


Let X = ABLet ∆A, ∆B and ∆X be the absolute errors in A, B and space space space space
space space space plus-or-minus ΔX over straight X equals plus-or-minus ΔA over straight A plus-or-minus ΔB over straight B
Maximum value of fractional error in X is 

ΔX over straight X equals ΔA over straight A plus ΔB over straight B

Multiplying both sides by 100

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#6 {main}</pre>
i.e. Maximum possible %age error in X
= Maximum possibe %age error in A + MAximum possible %age error in B.

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The least count of a stopwatch is 0.2 sec. The time period of 20 oscillations of a pendulum is measured to be 25.0 sec. What is the percentage error in this measurement?


The least count of stopwatch is = 0.2 s

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#6 {main}</pre>

Percentage error in measurement = <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>

                                                   = 0.8%
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Two gold pieces weigh 20.15 g and 20.17 g. What is the difference in the masses of the pieces to correct significant figures?

Mass of first gold piece = 20.17 g
Mass of second gold piece = 20.15 g

Difference in the masses of two pieces is,

                 Δm space equals space open parentheses 20.17 minus 20.15 close parentheses straight g
equals 0.02 straight g 

Here, masses of pieces are known upto second decimal place.

Difference is also upto second decimal place.

Hence the difference in the masses is 0.02g.      

 
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