For a satellite orbiting the earth, the necessary centripetal force is applied by gravitational pull.
That is,
Retarding torque is applied by the air friction. Hence, there is a decrease in the angular momentum. Therefore, the speed increases.
The potential energy function for a particle executing linear simple harmonic motion is given by V(x) =kx2/2, where k is the force constant of the oscillator. For k = 0.5 N m-1, the graph of V(x) versus x is shown in Fig. 6.12. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x = ± 2 m.
Here,
where
Total energy of particle E = 1J
Since at extreme position total energy is potential energy,
∴
or
or
Hence the results.