Given,
As,
Here, since electric field is directed radially inward charge q is negative.
Thus,
(a) To the left of the plates, electric fields are equal and opposite as plates are close to each other electric field is zero as surface charge density in outer side is zero.
(b) To the right of the plates, electric fields are equal and opposite as plates are close to each other electric field is zero.
(c) Electric fields between the plates are in same direction as total E.F. on both sides of plate due to surface charge density =
So, electric field of inner side of plate =
and for both plate
Given, Φ = –1.0 x 103 Nm2/C
r1 = 0.1 m, r2 = 0.2 m
(a) Doubling the radius of Gaussian surface will not affect the electric flux since the charge enclosed is the same in the two cases. Thus, the flux will remain be the same i.e., –1.0 x 103 Nm2/C
(b)