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The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of 10 dm3 to a volume of 100 dm3 at 27°C is

  • 38.3 J mol-1 K-1

  • 35.8 J  mol-1 K-1

  • 32.3 J  mol-1 K-1

  • 32.3 J  mol-1 K-1


A.

38.3 J mol-1 K-1

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The standard enthalpy of formation of NH3 is– 46.0 kJmol–1. If the enthalpy of formation of H2 from its atoms is – 436 kJ mol–1 and that of N2 is – 712 kJ mol–1,the average bond enthalpy of N – H bond is NH3 is

  • -964 kJ mol-1

  • +352 kJ mol-1

  • +1056 kJ mol-1

  • +1056 kJ mol-1


B.

+352 kJ mol-1

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The energy required to break one mole of Cl— Cl bonds in Cl2 is 242 kJ mol. The longest wavelength of light capable of breaking a single Cl — Cl bond is
(c= 3 x 108 ms–1and NA = 6.02 x 1023 mol–1)

  • 594 nm

  • 640 nm

  • 700 nm

  • 700 nm


D.

700 nm

Energy, E = NA

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The incorrect expression among the following is

  • fraction numerator increment space straight G subscript system over denominator increment straight G subscript total end fraction space equals space minus straight T
  • In isothermal process

    straight W subscript reversible space equals negative nRT space ln straight V subscript straight f over straight V subscript straight i

  • In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction
  • In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction

C.

In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction

Option C has incorrect expression. The correct expression is,

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The standard reduction potentials for Zn2+/ Zn, Ni2+/ Ni, and F2+/ Fe are –0.76, –0.23 and –0.44 V respectively. The reaction X + Y2+ → X 2+ + Y will be spontaneous when

  • X = Ni, Y = Fe

  • X = Ni, Y = Zn

  • X =Fe, Y= Zn

  • X =Fe, Y= Zn


D.

X =Fe, Y= Zn

X = Zn, Y = Ni
Zn + Ni2+  →Zn2+ + Ni

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