A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles area required to cover a floor of area 1080 m2?
(If required you can split the tiles in whatever way want to fill up the corners.)
Area of a parallelograms = Base x Corresponding height
           Area of a tile =
∴     Area of the floor  = 1080 m2
     Now, number of tiles =Â
                     =Â
                     = 45000 tiles
A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?
(a) Side of the square = 60 m
∴     Its perimeter = 4 x side
                = 4 x 60 m
                = 240 m
       Area of the square = Side x Side
                      = 60 m x 60 m
                       = 3600 m2
(b) ∵  Perimeter of the rectangle = Perimeter of the given square
   ∴  Perimeter of the rectangle = 240 m
   or   2 x [Length + Breadth] = 240 m
   or   2 x [80 m + Breadth] = 240 m
    or        80 m + Breadth =Â
    ∴             Breadth  = (120 - 80) m = 40 m
    Now,        Area of the rectangle  = Length x Breadth
                                 = 80 m x 40 m
                                 = 3200 m2
     Since,  3600 m2 > 3200 m2
      ∴  Area of the square field (a) is greater.
(a)
(b) (i) The given figure is a rectangle in which
   Length = 14 cm
   Breadth = 7 cm
∵      Perimeter of a rectangle = 2 x [Length + Breadth]
∴     Perimeter of the given figure = 2 x [14 cm + 7 cm]
                            = 2 x 21 cm
                            = 42 cm
                                      Â
   (ii)  The figure is a square  housing its side as 7 cm.
      ∵         Perimeter of a square = 4 x side
      ∴     Perimeter of the given figure = 4 x 7 cm
                                  = 28 cm.Â
                Â
     Â
The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden. [Length of rectangle is 20 - (3.5 + 3.5) meters.]
Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs 55 per m2.
∵  The given plot is a square with side as 25 m.
∴   Area of the plot = Side x Side
                 = 25 m x 25 m = 625 m2
∵  The constructed portion is a rectangle having length = 20 m and breadth = 15 m.
∴   Area of the constructed portion = 20 m x 15 m
                             = 300 m2
          Now area of the garden = [Total plot area] - [Total constructed area]
                              = (625 - 300)m2
                              = 325 m2
∴  Cost of developing the garden =  Rs 55 x 325
                           = Rs 17, 875