Chapter Chosen

Playing with Numbers

Book Chosen

Mathematics

Subject Chosen

Mathematics

Book Store

Download books and chapters from book store.
Currently only available for.
CBSE Gujarat Board Haryana Board

Previous Year Papers

Download the PDF Question Papers Free for off line practice and view the Solutions online.
Currently only available for.
Class 10 Class 12
zigya tab

Write the following in the usual form.
(i) 10 x 5 + 6             (ii)  100 x 7 + 10 x 1 + 8        (iii) 100 x a + 10 x c + b


(i) 10 x 5 + 6 = 50 + 6 = 56
(ii) 100 x 7 + 10 x 1 + 8 = 700 + 10 + 8 = 718
(iii) 100 x a + 10 x c + b = 100 a + 10c + b = <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>

1122 Views

Check what result would have been if Sundaram had chosen the numbers shown. 1.17 2.21 3.96 4.37.


1.                           Chosen number  = 17
             Number with reversed digits  =  71
                                    Difference  = 71 - 17 = 54
                                                   = 9 x [6]
        

2.                                    Chosen number = 21
                       Number with reversed digits = 12
                                             Difference  = 21 - 12 = 9
                                                            = 9 x [1]
           = 9 x [Difference between the digits of the chosen number (2 - 1 = 1)]


3.                      Chosen number = 96
         Number with reversed digits = 69
                               Difference  = 96 - 69 = 27
                                              = 9 x [3]
= 9 x [Difference between the digits of the chosen number (9 - 6)]


4.                                  Chosen number = 37
                    Number with reversed digits  = 73
                                            Difference = 73 - 37 = 36
                                                          = 9 x [4]

      = 9 x [Difference between the digits of the chosen number (7 - 3 = 4)]

540 Views

Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.


1. 132                      Chosen number = 132
                            Reversed number = 231
                                     Difference  = 231 - 132
                                                    = 99
We have                          99 + 99 = 1, remainder = 0

2. 469                       Chosen  number = 469
                              Reversed number = 964
                                       Difference = 964 - 469 = 495
We have                           495 + 99 = 5, remainder = 0



3.                             Chosen  number = 737
                             Reversed number  = 737
                          We have dirrerence = 737 - 737 = 0
                                              0 + 99 = 0, remainder = 0

4.                              Chosen number   = 901
                               Reversed number  = 109
                                        Differende  = 901 - 109
                                                       =  792
         We have               792 + 99 = 8, remainder = 0
Forming three digit number with given three dgits.

519 Views

Write the following numbers in generalized form.

(i) 25 (ii) 73 (iii) 129 (iv) 302

 


(i)       25 = 20 + 5
               = 10 x 2 + 5 x 1 = 10 x 2 + 5

(ii)       73 = 70 + 3
                = 10 x 7 + 3 x 1 = 10 x 7 + 3

(iii)      129 = 100 + 20 + 9
                = 100 x 1 + 20 x 2 + 1 x 9 = 100 x 1 + 10 x 2 + 9

(iv)       302 = 100 x 3 + 10 x 0 + 1 x 2 = 300 + 0 + 2

2111 Views

Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17


1.                      Chosen number = 27
         Number with reversed digits = 72
            Sum of the two numbers  = 27 + 72 = 99
Now,                                   99  = 11[9]
                                              = 11[2 + 7]
                                              = 11(Sum of the digits of the chosen number)


2.                         Chosen number = 39
            Number with reversed digits = 93
                Sum of the two numbers = 39 + 93 = 132
Now,                              132 + 11 = 12

i,e,                                 132 = 11[12]
                                           = 11 [ 3 + 9]
                                           = 11 [ Sum of the digits of the chosen number]            


3.                                     Chosen number = 64
                       Number with reversed digits  = 46
                                                    Sum   = 64 + 46 = 110
Now,                                                110 = 11[10]
                                                            = 11[6 + 4]
                                                 = 11[ Sum of the digits of the chosen number  

4.                                      Chosen number    =  17
                        Number with reversed digits     = 71
                                                        Sum   =  17 + 71 = 88
Now,                                                    88    = 11[8]
                                                                 = 11[1+7]
                                                   = 11[Sum of the digits of the chosen number]
                          

828 Views