Subject

Mathematics

Class

CBSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

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21.

The scalar product of the vector straight a with rightwards arrow on top equals space straight i with hat on top plus straight j with hat on top plus straight k with hat on top with a unit vector along the sum of vectors straight b with rightwards arrow on top equals 2 straight i with hat on top plus 4 straight j with hat on top minus 5 straight k with hat on top space space and space straight c with rightwards arrow on top space equals space straight lambda straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top is equal to one. Find the value of straight lambda and hence find the unit vector along straight b with rightwards arrow on top plus straight c with rightwards arrow on top.


Given that
straight b with rightwards arrow on top space equals space 2 straight i with hat on top plus 4 straight j minus 5 straight k
straight c with rightwards arrow on top equals straight lambda straight i with hat on top plus 2 straight j plus 3 straight k
Now consider the sum of vectors straight b with rightwards arrow on top plus straight c with rightwards arrow on top colon
straight b with rightwards arrow on top plus straight c with rightwards arrow on top equals space open parentheses 2 straight i with hat on top plus 4 straight j minus 5 straight k close parentheses plus open parentheses straight lambda straight i with hat on top plus 2 straight j plus 3 straight k close parentheses
space space rightwards double arrow space space straight b with rightwards arrow on top plus straight c with rightwards arrow on top space equals space left parenthesis 2 plus straight lambda right parenthesis straight i with hat on top plus 6 straight j minus 2 straight k
Let space straight n with hat on top space be space the space unit space vector space along space the space sum space of space vectors space straight b with rightwards arrow on top plus straight c with rightwards arrow on top colon
straight n with hat on top space equals fraction numerator left parenthesis 2 plus straight lambda right parenthesis straight i with hat on top plus 6 straight j minus 2 straight k over denominator square root of left parenthesis 2 plus straight lambda right parenthesis squared plus 6 squared plus 2 squared end root end fraction
The space scalar space product space of space straight a with rightwards arrow on top space and space straight n space is space 1. space Thus comma space
straight a with rightwards arrow on top. straight n with hat on top space equals open parentheses straight i with hat on top plus straight j plus straight k close parentheses. space open parentheses fraction numerator left parenthesis 2 plus straight lambda right parenthesis straight i with hat on top plus 6 straight j minus 2 straight k over denominator square root of left parenthesis 2 plus straight lambda right parenthesis squared plus 6 squared plus 2 squared end root end fraction close parentheses
rightwards double arrow 1 space equals fraction numerator 1 left parenthesis 2 plus straight lambda right parenthesis plus 1.6 minus 1.2 over denominator square root of left parenthesis 2 plus straight lambda right parenthesis squared plus 6 squared plus 2 squared end root end fraction
rightwards double arrow square root of left parenthesis 2 plus straight lambda right parenthesis squared plus 6 squared plus 2 squared end root space equals space 2 plus straight lambda plus 6 minus 2
rightwards double arrow square root of left parenthesis 2 plus straight lambda right parenthesis squared plus 6 squared plus 2 squared end root space equals straight lambda plus 6
rightwards double arrow left parenthesis 2 plus straight lambda right parenthesis squared plus 40 space equals space left parenthesis straight lambda plus 6 right parenthesis squared
rightwards double arrow straight lambda squared plus 4 straight lambda plus 4 plus 40 equals straight lambda squared plus 12 straight lambda plus 36
rightwards double arrow 4 straight lambda plus 44 equals 12 straight lambda plus 36
rightwards double arrow 8 straight lambda equals 8
rightwards double arrow straight lambda equals 1
Thus, n is:
straight n equals fraction numerator left parenthesis 2 plus 1 right parenthesis straight i with hat on top plus 6 straight j minus 2 straight k over denominator square root of left parenthesis 2 plus 1 right parenthesis squared plus 6 squared plus 2 squared end root end fraction
rightwards double arrow space straight n space equals space fraction numerator 3 straight i with hat on top plus 6 straight j minus 2 straight k over denominator square root of 3 squared plus 6 squared plus 2 squared end root end fraction
rightwards double arrow straight n space equals fraction numerator 3 straight i with hat on top plus 6 straight j minus 2 straight k over denominator square root of 49 end fraction
rightwards double arrow straight n space equals space fraction numerator 3 straight i with hat on top plus 6 straight j minus 2 straight k over denominator 7 end fraction
rightwards double arrow straight n space equals 3 over 7 straight i with hat on top plus 6 over 7 straight j minus 2 over 7 straight k



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22. Evaluate colon
integral subscript 0 superscript straight pi fraction numerator 4 straight x space sinx over denominator 1 plus cos squared straight x end fraction dx
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23.

Evaluate:
integral fraction numerator straight x plus 2 over denominator square root of straight x squared plus 5 straight x plus 6 end root end fraction dx

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24.

An experiment succeeds thrice as often as it fails. Find the probability that in the next five trials, there will be at least 3 successes.

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25. If space straight y space equals space Pe to the power of ax plus Qe to the power of bx show that
straight d to the power of 2 straight y end exponent over dx squared minus left parenthesis straight a plus straight b right parenthesis dy over dx plus aby space equals 0
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26. If space straight x equals cost left parenthesis 3 minus 2 cos squared straight t right parenthesis space and space straight y equals sint left parenthesis 3 minus 2 sin squared straight t right parenthesis comma space find space the space value space of space dy over dx at space straight t equals straight pi over 4.
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27.

Find the particular solution of the differential equation log open parentheses dy over dx close parentheses equals 3 straight x plus 4 straight y comma space given space that space straight y space equals space 0 comma space when space straight x equals space 0.

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28.

Find the value of p, so that the lines:
are perpendicular to each other. Also find the equations of a line passing through a point (3, 2, -4) and parallel to line l1.

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 Multiple Choice QuestionsLong Answer Type

29.

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x- y + z = 0. Also find the distance of the plane obtained above, from the origin.

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30.

Find the distance of the point (2, 12, 5) from the point of intersection of the line 
straight r with rightwards arrow on top equals 2 straight i with hat on top minus 4 straight j with hat on top plus 2 straight k with hat on top plus straight lambda open parentheses 3 straight i with hat on top plus 4 straight j with hat on top plus 2 straight k with hat on top close parentheses space and space the space plane space straight r with rightwards arrow on top. open parentheses straight i with hat on top minus 2 straight j with hat on top plus straight k with hat on top close parentheses equals 0.

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