Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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21.

An organic compound having molecular mass 60 is found to contain C = 20%, H = 6.67% and N = 46.67% while rest is oxygen. On heating, it gives NH3 along with a solid residue. The solid residue give violet colour with alkaline copper sulphate solution. The compound is

  • CH3NCO

  • CH3CONH2

  • (NH2)2CO

  • (NH2)2CO


C.

(NH2)2CO

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22.

Which of the following oxides is amphoteric in character?

  • CaO

  • CO2

  • SiO2

  • SiO2

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23.

If α is the degree of dissociation of Na2SO4, the vant Hoff’s factor (i) used for calculating the molecular mass is

  • 1 + α

  • 1 - α

  • 1 +2α

  • 1 +2α

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24.

The oxidation state of Cr in [Cr(NH3)4Cl2]+ is

  • +3

  • +1

  • 0

  • 0

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25.

Hydrogen bomb is based on the principle of

  • Nuclear fission

  • Natural radioactivity

  • Nuclear fusion

  • Nuclear fusion

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26.

An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be

  • A2B

  • AB

  • AB3

  • AB3

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27.

Lattice energy of an ionic compounds depends upon

  • Charge on the ion only

  • Size of the ion only

  • Packing of ions only

  • Packing of ions only

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28.

The highest electrical conductivity of the following aqueous solutions is of

  • 0.1 M acetic acid

  • 0.1 M chloroacetic acid

  • 0.1 M fluoroacetic acid

  • 0.1 M fluoroacetic acid

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29.

Aluminium oxide may be electrolysed at 1000o  C to furnish aluminium metal (Atomic mass = 27 amu; 1 Faraday = 96,500 Coulombs). The cathode reaction is

Al3+ +3e- → Alo
To prepare 5.12 kg of aluminium metal by this method would require

  • 5.49 x 107 C of electricity

  • 1.83 x 107 C of electricity

  • 1.49x 107 C of electricity

  • 1.49x 107 C of electricity

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30.

Consider an endothermic reaction, X → Y with the activation energies Eb and Ef for the backward and forward reactions, respectively. In general

  • Eb < Ef

  • Eb > EfEb > Ef

  • Eb = Ef

  • Eb = Ef

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