The range of the function 7-xPx-3 is
{1, 2, 3}
{1, 2, 3, 4, 5}
{1, 2, 3, 4}
{1, 2, 3, 4}
A.
{1, 2, 3}
The given function f(x) = 7-xPx-3 would be defined if
(i) 7 - x > 0 ⇒ x < 7
(ii) x - 3 > 0 ⇒ x > 3
(iii) (x - 3) < (7 - x)
⇒ 2x < 10 ⇒ x < 5
⇒ x = 3, 4, 5
Hence Range of f(x) = {4P0, 3P1, 2P2}
Range of f(x) = {1, 3, 2}
Let A The only correct statement about the matrix A is
A is a zero matrix
A2 = I
A−1 does not exist
A−1 does not exist
If f : R S, defined by , is onto, then the interval of S is
[0, 3]
[-1, 1]
[0, 1]
[0, 1]
A function y = f(x) has a second order derivative f″(x) = 6(x – 1). If its graph passes through the point (2, 1) and at that point the tangent to the graph is y = 3x – 5, then the function is
(x-1)2
(x-1)3
(x+1)3
(x+1)3
The normal to the curve x = a(1 + cosθ), y = asinθ at ‘θ’ always passes through the fixed point
(a, 0)
(0, a)No
(0,0)
(0,0)
The differential equation for the family of curves,x2 +y2 -2ay = 0 where a is an arbitrary constant is
2(x2-y2)y' = xy
(x2+y2)y' = xy
2(x2+y2)y' = xy
2(x2+y2)y' = xy
The solution of the differential equation ydx + (x + x2y) dy = 0 is
-1/ XY =C
-1/XY + log y = C
1/XY + log y = C
1/XY + log y = C