Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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51.

Let f and g be differentiable functions satisfying g′(a) = 2, g(a) = b and fog = I (identity function). Then f ′(b) is equal to

  • 1/2

  • 2

  • 2/3

  • 2/3


A.

1/2

Given fog = I
⇒ fog(x) = x for all x
⇒ f ′(g(x)) g′(x) = 1 for all x

f ′(g(a)) =1/g('a) = 1/2
⇒f(b') = 1/2

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52. limit as straight n rightwards arrow infinity of space sum from straight r equals 1 to straight n of space 1 over straight n straight e to the power of straight r over straight n end exponent space is space
  • e

  • e+1

  • e-1
  • e-1
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53.

If integral space fraction numerator sin space straight x over denominator sin space left parenthesis straight x minus straight alpha right parenthesis end fraction space dx space equals space Ax space plus space straight B space log space sin space left parenthesis straight x minus straight alpha right parenthesis space plus straight C comma space space then space value space left parenthesis straight A comma space straight B right parenthesis is

  • (sinα, cosα)

  • (cosα, sinα)

  • (- sinα, cosα)

  • (- sinα, cosα)

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54. integral fraction numerator dx over denominator cos space straight x space minus space sin space straight x end fraction is equal to
  • fraction numerator 1 over denominator square root of 2 end fraction space log space open vertical bar tan open parentheses straight x over 2 minus fraction numerator begin display style straight pi end style over denominator 8 end fraction close parentheses close vertical bar space plus straight C
  • fraction numerator 1 over denominator square root of 2 end fraction space log space open vertical bar cot open parentheses straight x over 2 close parentheses close vertical bar space plus straight C
  • fraction numerator 1 over denominator square root of 2 end fraction space log space open vertical bar tan open parentheses straight x over 2 minus fraction numerator 3 straight pi over denominator 8 end fraction close parentheses close vertical bar space plus straight C
  • fraction numerator 1 over denominator square root of 2 end fraction space log space open vertical bar tan open parentheses straight x over 2 minus fraction numerator 3 straight pi over denominator 8 end fraction close parentheses close vertical bar space plus straight C
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55.

The value of integral subscript negative 2 end subscript superscript 3 space vertical line 1 minus straight x squared vertical line dx space is

  • 28/7

  • 28/3

  • 7/3

  • 7/3

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56.

The value of integral subscript 0 superscript pi divided by 2 end superscript fraction numerator left parenthesis sin space x space plus space cos space x right parenthesis squared over denominator square root of 1 plus space sin space 2 x end root end fraction space d x space i s

  • 0

  • 1

  • 2

  • 2

104 Views

57.

Ifintegral subscript 0 superscript straight pi space xf space left parenthesis sin right parenthesis space dx space equals space straight A space integral subscript 0 superscript straight pi divided by 2 end superscript space straight f space left parenthesis sin space straight x right parenthesis space dx comma space then space straight A space is

  • 0

  • π

  • π/2

  • π/2

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58.

If straight f left parenthesis straight x right parenthesis space equals space fraction numerator straight e to the power of straight x over denominator 1 plus straight e to the power of straight x end fraction. space straight I subscript 1 space equals space integral subscript straight f left parenthesis negative straight a right parenthesis end subscript superscript straight f left parenthesis straight a right parenthesis end superscript space xg open curly brackets straight x open parentheses 1 minus straight x close parentheses close curly brackets dx space and space straight I subscript 2 space equals space integral subscript straight f left parenthesis negative straight a right parenthesis end subscript superscript straight f left parenthesis straight a right parenthesis end superscript space straight g open curly brackets straight x open parentheses 1 minus straight x close parentheses close curly brackets dx then the value of I2/I1 is

  • 2

  • -2

  • 1

  • 1

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59.

The area of the region bounded by the curves y = |x – 2|, x = 1, x = 3 and the x-axis is

  • 1

  • 2

  • 3

  • 3

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60.

Let A (2, –3) and B(–2, 1) be vertices of a triangle ABC. If the centroid of this triangle moves on the line 2x + 3y = 1, then the locus of the vertex C is the line

  • 2x + 3y = 9

  • 2x – 3y = 7

  • 3x + 2y = 5

  • 3x + 2y = 5

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