Subject

Mathematics

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

21.

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

  • 3

  • 36

  • 66

  • 66


D.

66

The number  of ways in which two balls from urn A and two balls from urn B can be selected
 = 3C2 x 9C2 =  3x 36  = 108

150 Views

Advertisement
22.

The area bounded by the curve y = cos x and y = sin x between the ordinates x = 0 and x = 3π/2 is 

  • left parenthesis 4 minus square root of 2 minus 2 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 plus 2 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 minus 1 right parenthesis space sq space units
  • left parenthesis 4 minus square root of 2 minus 1 right parenthesis space sq space units
444 Views

23.

Solution of the differential equation
cos x dy = y (sin x - y) dx, 0 < x < π/2, is 

  • sec x = (tan x + C ) y 

  •  y sec x = tan x + C

  •  y tan x = sec x + C 

  •  y tan x = sec x + C 

243 Views

24.

A line AB in three-dimensional space makes angles 45° and 120° with the positive x-axis and the positive y-axis respectively. If AB makes an acute angle θ with the positive z-axis, then θ

  • 30°

  • 45°

  • 60°

  • 60°

118 Views

Advertisement
25.

The circle x2+ y2 = 4x + 8y + 5 intersects the line 3x – 4y = m at two distinct points if

  • -85 < m < -35

  • -35 < m < 15

  • 15 < m < 65

  • 15 < m < 65

247 Views

26.

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

  • 1/3

  • 2/7

  • 1/21

  • 1/21

115 Views

27.

Let bold a bold space bold equals bold j with bold hat on top bold minus bold k with bold hat on top bold space and bold c bold space bold equals bold space bold i with bold hat on top bold minus bold j with bold hat on top bold minus bold k with bold hat on top. Then, the vector b satisfying a x b + c = 0  and a.b  = 3

  • negative straight i with hat on top plus straight j with hat on top space minus 2 straight k with hat on top
  • 2 straight i with hat on top minus straight j with hat on top space plus 2 straight k with hat on top
  • negative straight i with hat on top minus straight j with hat on top space minus 2 straight k with hat on top
  • negative straight i with hat on top minus straight j with hat on top space minus 2 straight k with hat on top
162 Views

28.

If the vectors bold a bold space bold equals bold space bold i with bold hat on top bold space bold minus bold j with bold hat on top bold space bold plus bold 2 bold k with bold hat on top bold comma bold space bold b bold space bold equals bold 2 bold i with bold hat on top bold space bold plus bold 4 bold j with bold hat on top bold space bold plus bold k with bold hat on top bold space bold and bold space bold c bold space bold equals bold space bold lambda bold i with bold hat on top bold space bold plus bold j with bold hat on top bold space bold plus bold mu bold k with bold hat on top are mutually orthogonal, then (λ,μ) is equal to

  • (-3,2)

  • (2,-3)

  • (-2,3)

  • (-2,3)

129 Views

Advertisement
29.

The line L given by straight x over 5 space plus straight y over straight b space equals space 1 passes through the point (13, 32). The line K is parallel to L and has the equation straight x over straight c space plus straight y over 3 space equals space 1 . Then the distance
between L and K is

  • fraction numerator 23 over denominator square root of 15 end fraction
  • square root of 17
  • fraction numerator 17 over denominator square root of 15 end fraction
  • fraction numerator 17 over denominator square root of 15 end fraction
166 Views

30.

Four numbers are chosen at random (without replacement) from the set {1, 2, 3, ..., 20}.

Statement-1: The probability that the chosen numbers when arranged in some order will form an AP is 1 85.
Statement-2: If the four chosen numbers form an AP, then the set of all possible values of common difference is {±1, ±2, ±3, ±4, ±5}.

  • Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

  • Statement-1 is true, Statement-2 is true; statement-2 is not a correct explanation for Statement-1.

  • Statement-1 is true, Statement-2 is false.

  • Statement-1 is true, Statement-2 is false.

214 Views

Advertisement