Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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11.

The part of circle x2 + y2 = 9 in between y = 0 and y = 2 is revolved about y-axis. The volume of generating solid will be

  • 463π

  • 12π

  • 16π

  • None of these


A.

463π

The part of circle x2 + y2 = 9 in between y = 0 and y = 2 is revolved about y-axis. Then, a frustum of sphere will be formed.

The volume of this frustum

   = π02x2dy = π029 - y2dy= π9y - 13y302= π9 × 2 - 1323 - 9 . 0 - 13 . 0= π18 - 83= 463π cu units


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12.

The solution of the differential equation xdy - ydx = x2 + y2dx is

  • y - x2 + y2 = Cx2

  • y + x2 + y2 = Cx2

  • y + x2 + y2 + Cx2 = 0

  • None of the above


13.

The solution of dydx = cosx2 - ycscx where y = 2, when x = π2 is

  • y = sinx + cscx

  • y = tanx2 + cotx2

  • y = 12secx2 + 2cosx2

  • None of the above


14.

The solution of the equation sin-1dydx = x + y is

  • tanx + y + secx + y = x + C

  • tanx + y - secx + y = x + C

  • tanx + y - secx + y + x + C = 0

  • None of the above


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15.

The angle between two diagonals of a cube will be

  • sin-113

  • cos-113

  • variable

  • None of these


16.

The lines x - a + dα - δ = y - aα = z - a - dα + δ and x - b + cβ - τ = y - bβ = z - b - cβ + τ are coplanar and then equation to the plane in which they lie, is

  • x + y + z = 0

  • x - y + z = 0

  • x - 2y + z = 0

  • x + y - 2z = 0


17.

If 0t2x fxdx = 25t5,t > 0, then f425 is

  • 25

  • 52

  • - 25

  • None of these


18.

Three forces of magnitudes 1, 2 and 3 dynes meet in a point and act along diagonals of three adjacent faces of a cube. The resultant force is

  • 114 dynes

  • 6 dynes

  • 5 dynes

  • None of the above


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19.

The vectors AB = 3i + 5j + 4k and AC = 5i - 5j + 2k are side of a ABC. The length ofthe median through A is

  • 13 units

  • 25 units

  • 5 units

  • 10 units


20.

Let a = 2i + j + k, b = i + 2j - 1, and a unit vector c be caplanar. If c is perpendicular to a, then c is

  • 12- j  + k

  • 13- i - j - k

  • 15i - 2j

  • 13i - j  - k


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