Which one of is not likely to exist and why?
The oxidation state of P in is +5 while in
is +3. As we know that the stability of the +5 oxidation state is highest on top of the group and decrease down the group and stability of +3 is low on the top of the group and increase down the group.
Therefore is more likely to exist.
Arrange the following in the decreasing order of their basic strength in aqueous solutions:
CH3NH2, (CH3)2NH, (CH3)3 N and NH3
(a) Complete the following chemical reactions equations:
(i) P4+SO2Cl2 -->
(ii) XeF6+H2O -->
(b) Predict the shape and the asked angle (90° or more or less) in each of the following cases:
(i) and the angle O - S - O
(ii) ClF3 and the angle F - Cl - F
(iii) XeF2 and the angle F - Xe - F
Complete the following chemical equations:
(i) NaOH+Cl2 -->
(ii) XeF4+O2F2--->
(b) Draw the structures of the following molecules:
(i) H3PO2
(ii) H2S2O7
(iii) XeOF4
State reasons for each of the following:
The N-O bond in is shorter than the N-O bond in
State reasons for each of the following:
(i) All the P-Cl bonds in PCl5 molecule are not equivalent.
(ii) Sulphur has a greater tendency for catenation than oxygen.
(i) NF3 is an exothermic compound whereas NCl3 is not.
(ii) F2 is most reactive of all the four common halogens.
(b) Complete the following chemical equations:
(i) C + H2SO4 (conc.)-->
(ii) P4 + NaOH + H2O-->
(iii) Cl2+F2 ------>
(excess)
(a) Account for the following:
(i) The acidic strength decreases in the order HCl > H2S > PH3
(ii) Tendency to form pentahalides decreases down the group in group 15 of the periodic table.
(b) Complete the following chemical equations:
(i) P4 + SO2Cl2-->
(ii) XeF2 + H2O--->
(iii) I2+HNO3(conc.)--->