The general solution of the differential equation dydx 

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

541.

The differential equation of the family of circles touching Y-axis at the origin is

  • x2 + y2dydx - 2xy = 0

  • x2 - y2 + 2xydydx = 0

  • x2 - y2dydx - 2xy = 0

  • x2 + y2dydx + 2xy = 0


542.

The degree and order of the differential equation 1 + dydx373 = 7d2ydx2 respectively are

  • 3 and 7

  • 3 and 2

  • 7 and 3

  • 2 and 3


543.

The particular solution of the differential equation

y1 + logxdxdy - xlogx = 0, when, x = e, y = e2 is

  • y = exlog(x)

  • ey = xlog(x)

  • xy = elog(x)

  • ylog(x) = ex


544.

If sinx  is the integrating factor (IF) of the linear differential equation dydx + Py = Q, then P is

  • logsinx

  • cosx

  • tanx

  • cotx


Advertisement
545.

The solution of the differential equation

dydx = tanyx + yx is

  • cosyx = cx

  • sinyx = cx

  • cosyx = cy

  • sinyx = cy


546.

The differential equation of all parabolas whose axis is Y-axis, is

  • xd2ydx2 - dydx = 0

  • xd2ydx2 + dydx = 0

  • d2ydx2 - y = 0

  • d2ydx2 - dydx = 0


547.

The particular solution of the differential equation xdy + 2ydx = 0, when x = 2, y = 1 is

  • xy = 4

  • x2y = 4

  • xy2 = 4

  • x2y2 = 4


548.

The general solution of the equation dydx = y2 - x2yx + 1 is

  • y2 = (1 + x)log(1 + x) - c

  • y2 = 1 + xlogc1 - x - 1

  • y2 = 1 - xlogc1 - x - 1

  • y2 = 1 + xlogc1 + x - 1


Advertisement
Advertisement

549.

The general solution of the differential equation dydx + sinx + y2 = sinx - y2 is

  • logetany2 = - 2sinx2 +C

  • logetany4 = 2sinx2 +C

  • logetany2 = - 2sinx2 +C

  • logetany4 = - 2sinx2 +C


D.

logetany4 = - 2sinx2 +C

We have,dydx + sinx + y2 = sinx - y2 dydx = sinx - y2 - sinx + y2 dydx = 2cosx - y2 + x + y22sinx - y2 - x + y22          sinC - sinD = 2cosC + D2 . sinC - D2 dydx = 2cosx2sin- y2 dydx = - cosx2siny2 dysiny2 = - 2cosx2dx        Variables are separated cscy2dy = - 2cosx2dxOn integrating both sides, we get

        cscy2dy = - 2cosx2dx 2logetany4 = - 4sinx2 +C   logetany4 = - 2sinx2 +C


Advertisement
550.

The function y specified implicitly by the relation 0yetdt + 0xcostdt = 0 satisfies the differential equation

  • e2yd2ydx2 + dydx2 = sinx

  • eyd2ydx2 + dydx2 = sin2x

  • ey2d2ydx2 + dydx2 = sinx

  • eyd2ydx2 + dydx2 = sinx


Advertisement