∫0π4sinx + cosx3 + sin2xdx is fr

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 Multiple Choice QuestionsMultiple Choice Questions

781.

If 01fxdx = 5, then the value of ... + 01x9fx10dx is equal to

  • 125

  • 625

  • 275

  • 55


782.

If fxsinx . cosxdx = 12b2 - a2logfx +c, where c is the constant of integration, then f(x) is

  • 2abcos2x

  • 2b2 - a2cos2x

  • 2absin2x

  • 2b2 - a2sin2x


783.

If xxx + 1dx = ktan-1m, then (k, m) is

  • (2, x)

  • (1, x)

  • 1, x

  • 2, x


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784.

0π4sinx + cosx3 + sin2xdx is

  • 14log3

  • log3

  • 12log3

  • 2log3


A.

14log3

0π4sinx + cosx3 + sin2xdx= 0π4sinx + cosx4 - 1 - sin2xdx= 0π4sinx + cosx4 - sinx + cosx2dxPut t = sinx - cosx    dt = cosx + sinxdx= - 10dt4 - t2= - 10dt2 + t2 - t= 14log2 +t - log2 - t- 10= 14log2 + t2 - t- 10= 14log1 - log13= 14log3


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785.

01x1 - x32dx is

  • - 235

  • 435

  • 2435

  • - 835


786.

The value of 04x - 1dx is

  • 52

  • 5

  • 4

  • 1


787.

If In0π4tannxdx, where where n is apositive integer, then I10 + I8 is

  • 19

  • 18

  • 17

  • 9


788.

If Inexsinx + cosx1 - sin2xdx is

  • ex . cscx +C

  • ex . cotx + C

  • ex . secx + C

  • ex . tanx + C


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789.

When x > 0, then cos-11 - x21 +x2dx is

  • 2xtan-1x - log1 +x2 + C

  • 2xtan-1x + log1 +x2 + C

  • 2xtan-1x + log1 +x2 + C

  • 2xtan-1x - log1 +x2 + C


790.

If the area between y = mx2 and x = my2 (m > 0) is 1/4 sq units, then the value of m is

  • ± 32

  • ± 23

  • 2

  • 3


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