If the area between y = mx2 and x = my2 (m > 0) is 1/4 sq unit

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783.

If xxx + 1dx = ktan-1m, then (k, m) is

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784.

0π4sinx + cosx3 + sin2xdx is

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788.

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789.

When x > 0, then cos-11 - x21 +x2dx is

  • 2xtan-1x - log1 +x2 + C

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790.

If the area between y = mx2 and x = my2 (m > 0) is 1/4 sq units, then the value of m is

  • ± 32

  • ± 23

  • 2

  • 3


B.

± 23

Given curves; y = mx2 and y2m= x; m > 0Intersection point of both curves   x = mmx22 = m3x4     m3x4 - x = 0 xm3x3 - 1 = 0 xmx  - 1m2x2 + 1 + mx = 0 x = 0, x = 1/m and y = 0, y = 1/mWe take only the points       = (0, 0) and (1/m, 1/m)Now, the area of the curve= 01mxm - mx2dxGiven, 14 = 23m . x32 - m . x3301m      14 = 23m . 1m32 - m3 . 1m3     14 = 23m2 - 13m2    14 = 13m2  m2 = 43    m = ± 23


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