Subject

Chemistry

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

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 Multiple Choice QuestionsShort Answer Type

1.

‘Crystalline solids are anisotropic in nature’. What does this statement mean?

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2. Express the relation between conductivity and molar conductivity of a solution held in a cell.
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3.

Define electrophoresis ? 

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4.

Draw the structure of XeF2 molecule. 

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5.

The chemistry of corrosion of iron is essentially an electrochemical phenomenon. Explain the reactions occurring during the corrosion of iron in the atmosphere.

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6.

Determine the values of equilibrium constant (KC) and  incrementG° for the following reaction: 

Ni left parenthesis straight s right parenthesis space plus 2 Ag to the power of plus left parenthesis aq right parenthesis space rightwards arrow Ni to the power of 2 plus end exponent space left parenthesis aq right parenthesis space plus 2 Ag space left parenthesis straight s right parenthesis comma space straight E to the power of 0 equals 1.05 straight V space left parenthesis IF space equals 96500 space mol to the power of negative 1 end exponent right parenthesis space

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7. Distinguish between ‘rate expression’ and ‘rate constant’ of a reaction.
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8.

State reasons for each of the following: 

The N-O bond in  is shorter than the N-O bond in 


The shorter N - O bond in  is due to the existence of resonance in. The resonating structures can be drawn as follows.

Due to resonance in, the two bonds are equivalent. This leads to a decrease in bond length.

Thus, the N - O bond length in resembles a double bond.

Now, the resonating structures for can be drawn as: 

 

As seen from the above resonating structures of , the three oxygen atoms are sharing two single bonds and one double bond. So, the real N - O bond length resembles a single bond closely.  

In   the lone pair is delocalized between the 2 oxygen groups. Bond order equal to 1+1/2=3/2.

In  lone pair shared between three oxygen atom hence bond order =1+1/3=4/3.

Greater the bond order shorter the bond. Hence bond length of  less than that of 

This explains the existence of shorter bond length of the N - O bond  in  than in  .

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9.

State reasons for each of the following: 

SF6 is kinetically an inert substance. 

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10.

State reasons for each of the following: 

(i) All the P-Cl bonds in PCl5 molecule are not equivalent. 

(ii) Sulphur has a greater tendency for catenation than oxygen.

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