Subject

Mathematics

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

11.

Differentiate the function (sin x)x + sin–1 √xwith respect to x.

1700 Views

12.

If xm yn = (x + y)m + n, prove that fraction numerator straight d squared straight y over denominator dx squared end fraction space equals space 0

527 Views

13.

Evaluate: integral subscript 2 superscript 3 space 3 to the power of straight x space dx.

443 Views

14.

Find the vector equation of the line passing through the point A(1, 2, –1) and parallel to the line 5x – 25 = 14 – 7y = 35z.

1145 Views

Advertisement
15.

Prove that if E and F are independent events, then the events E and F' are also independent.

546 Views

16.

A small firm manufactures necklaces and bracelets. The total number of necklaces and bracelets that it can handle per day is at most 24. It takes one hour to make a bracelet and half an hour to make a necklace. The maximum number of hours available per day is 16. If the profit on a necklace is ` 100 and that on a bracelet is ` 300. Formulate on L.P.P. for finding how many of each should be produced daily to maximize the profit? It is being given that at least one of each must be produced.

1010 Views

17. Find space integral fraction numerator dx over denominator straight x squared space plus 4 straight x space plus 8 end fraction
406 Views

18.

Find integral fraction numerator 2 straight x over denominator left parenthesis straight x squared plus 1 right parenthesis left parenthesis straight x squared plus 2 right parenthesis squared end fraction dx

475 Views

Advertisement
Advertisement

19.

Evaluate: integral subscript 0 superscript straight pi fraction numerator straight x space sin space straight x over denominator 1 plus cos squared x end fraction dx


 integral subscript 0 superscript straight pi fraction numerator straight x space sin space straight x over denominator 1 plus cos squared x end fraction dx space space space...... space left parenthesis straight i right parenthesis
open square brackets By space using space integral subscript 0 superscript straight a space straight f left parenthesis straight x right parenthesis dx space equals space integral subscript 0 superscript straight a straight f left parenthesis straight a minus straight x right parenthesis dx close square brackets
we space get
space equals space integral subscript 0 superscript straight pi fraction numerator left parenthesis straight pi minus straight x right parenthesis space sin space left parenthesis straight pi minus straight x right parenthesis over denominator 1 plus cos squared space left parenthesis straight pi minus straight x right parenthesis end fraction dx space

space equals space integral subscript 0 superscript straight pi fraction numerator left parenthesis straight pi minus straight x right parenthesis space sin space straight x over denominator 1 plus cos squared space straight x end fraction dx space space....... space left parenthesis ii right parenthesis
Adding (i) and (ii) we get
2 straight I space equals space integral subscript 0 superscript straight pi space fraction numerator straight x space sin space straight x over denominator 1 space plus space cos squared straight x end fraction space dx space plus space integral subscript 0 superscript straight pi fraction numerator left parenthesis straight pi minus straight x right parenthesis space sin space straight x over denominator 1 plus space cos squared space straight x end fraction dx
space equals space integral subscript 0 superscript straight pi space fraction numerator left parenthesis straight x space plus straight pi space minus straight x right parenthesis space Sin space straight x over denominator 1 plus space cos squared straight x end fraction space dx
2 straight I space equals space integral subscript 0 superscript straight pi fraction numerator straight pi space sin space straight x over denominator 1 space space plus space cos squared straight x end fraction space dx
straight I space equals space integral subscript 0 superscript straight pi straight pi over 2 fraction numerator space sin space straight x over denominator 1 plus cos squared space straight x space end fraction dx

Let cos x = t,

-sin xdx = dt
also, x = 0, t = cos 0 = 1 and x = π, t= cos π=-1
straight I space equals space straight pi over 2 space integral subscript 1 superscript negative 1 end superscript space fraction numerator negative 1 over denominator 1 plus straight t squared end fraction dt
straight I space equals space minus straight pi over 2 open square brackets tan to the power of negative 1 end exponent space straight t close square brackets subscript 1 superscript negative 1 end superscript
space equals space minus straight pi over 2 open square brackets tan to the power of negative 1 end exponent space left parenthesis negative 1 right parenthesis minus tan to the power of negative 1 end exponent space left parenthesis 1 right parenthesis close square brackets
space equals space minus straight pi over 2 open square brackets negative straight pi over 4 minus straight pi over 4 close square brackets space equals straight pi over 2 space straight x space fraction numerator 2 straight pi over denominator 4 end fraction
straight I space equals space straight pi squared over 4

436 Views

Advertisement
20.

Evaluate:integral subscript 0 superscript 3 divided by 2 end superscript vertical line space straight x space sin space πx vertical line space dx

394 Views

Advertisement