Subject

Mathematics

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

Advertisement

21.

The random variable X can take only the values 0, 1, 2, 3. Given that P(X =0) = P(X = 1) = p and P(X = 2) = P(X = 3) such that Σpixi2 = 2Σpixi, find the value of p.


It is given that the random variable X can take only the values 0,1,2,3.
Given:
P(X = 0) = P( X =1) =p
P(X =2) =P(X =3)
Let P (X =2) = P(X =3) =q
Now,
P(X =0) + P(X =1) +P(X =2) +P(X =3) =1
⇒ p +p+(q+q) = 1
since Σpixi2 = 2Σpixi,
 rightwards double arrow space 0 space plus straight p left parenthesis 1 right parenthesis squared space plus open parentheses fraction numerator 1 minus 2 straight p over denominator 2 end fraction close parentheses open parentheses left parenthesis 2 squared plus 3 squared close parentheses space equals space 2 open square brackets 0 space plus straight p space plus open parentheses fraction numerator 1 minus 2 straight p over denominator 2 end fraction close parentheses left parenthesis 2 plus 3 right parenthesis close square brackets
rightwards double arrow space straight p space plus 13 over 2 left parenthesis 1 minus 2 straight p right parenthesis space equals 2 space open square brackets straight p space plus 5 over 2 left parenthesis 1 minus 2 straight p right parenthesis close square brackets
rightwards double arrow space straight p space plus 13 over 2 minus 12 straight p space equals space minus 8 straight p plus 5
rightwards double arrow space 4 straight p space equals space 3 over 2
rightwards double arrow space straight p space equals space 3 over 8

2028 Views

Advertisement
22.

Often it is taken that a truthful person commands, more respect in the society. A man is known to speak the truth 4 out of 5 times. He throws a die and reports that it is a six.
Find the probability that it is actually a six.
Do you also agree that the value of truthfulness leads to more respect in the society?

946 Views

23.

Solve the following L.P.P. graphically :
Minimise Z = 5x + 10y
Subject to x + 2y ≤ 120
Constraints x + y ≥ 60
x – 2y ≥ 0
and x, y ≥ 0

1041 Views

 Multiple Choice QuestionsLong Answer Type

24.

Use product open square brackets table row 1 cell negative 1 end cell 2 row 0 2 cell negative 3 end cell row 3 cell negative 2 end cell 4 end table close square brackets space space open square brackets table row cell negative 2 end cell 0 1 row 9 2 cell negative 3 end cell row 6 1 cell negative 2 end cell end table close square bracketsto solve the system of equations x + 3z = 9,
–x + 2y – 2z = 4, 2x – 3y + 4z = –3

733 Views

Advertisement
25.

Discuss the commutativity and associativity of binary operation '*' defined on A = Q − {1} by the rule a * b = a − b + ab for all, a, b ∊ A. Also find the identity element of * in A and hence find the invertible elements of A. 

738 Views

26.

Consider f : R+ → [−5, ∞), given by f(x) = 9x2 + 6x − 5. Show that f is invertible with f−1(y)open parentheses fraction numerator square root of straight y plus 6 end root minus 1 over denominator 3 end fraction close parentheses.

Hence Find
(i) f−1(10)
(ii) y if f−1(y)=43,

where R+ is the set of all non-negative real numbers.

479 Views

27.

If the sum of lengths of the hypotenuse and a side of a right angled triangle is given, show that the area of the triangle is maximum, when the angle between them is π/3.

839 Views

28.

Solve the differential equation straight x dy over dx space plus straight y space equals space straight x space cos space straight x space plus space sin space straight x comma space given space that space straight y space equals space 1 space when space straight x space equals space straight x over 2

417 Views

Advertisement
29.

Prove that x2 – y2 = c(x2 + y2)2 is the general solution of the differential equation (x3 – 3xy2)dx = (y3 – 3x2y) dy, where C is a parameter.

926 Views

30.

If straight a with rightwards arrow on top comma straight b with rightwards arrow on top comma space and space straight c with rightwards arrow on top are mutually perpendicular vectors of equal magnitudes, show that the vector stack straight a space with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top is equally straight a with rightwards arrow on top comma straight b with rightwards arrow on top comma space and space straight c with rightwards arrow on top inclined to Also, find the angle which stack straight a space with rightwards arrow on top space plus straight b with rightwards arrow on top space plus straight c with rightwards arrow on top with straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space or space straight c with rightwards arrow on top.

1088 Views

Advertisement