Carbocation as an intermediate is likely to be formed in the reaction
Propene + Cl2 2-chloropropane
Acetone + HCN acetonecyano hydrin
Ethylbromide + aq.KOH ethyl alcohol
Hexane 2-methyl pentane
The correct sequence of reactions to be performed to convert benzene into m-bromoaniline is
nitration, reduction, bromination
bromination, nitration, reduction
nitration, bromination, reduction
reduction, nitration, bromination
The correct statement is
Cyclohexadene and cyclohexene cannot be isolated with ease during controlled hydrogenation of benzene
One mole each of benzene and hydrogen when reacted gives 1/3 mole of cyclohexane and 2/3 mole unreacted hydrogen
Hydrogenation of benzene to cyclohexane is an endothermic process
It is easier to hydrogenate benzene when compared to cyclohexene
The statement that is not correct is
Hypophosphorous acid reduces silver nitrate to silver
In solid state PCl5 exists as [PCl4]+ [PCl6]-
Pure phosphine is non-inflammable
Phosphorous acid on heating disproportionates to give metaphosphonic acid and phosphine
In which one of the pairs of ion given, there is an ion that forms a coordination compound with both aqueous sodium hydroxide and ammonia and an other ion that forms a coordination compound only with aqueous sodium hydroxide?
Pb2+, Cu2+
Zn2+, Al3+
Cu2+, Zn2+
Al3+, Cu2+
A crystalline solid X reacts with dil. HCl to liberate a gas Y. Y decolourises acidified KMnO4. When a gas 'Z' is slowly passed into an aqueous solution of Y, colloidal sulphur is obtained X and Z could be respectively
Na2S, SO3
Na2SO4, H2S
Na2SO3, H2S
Na2SO4, SO2
A solution of 1.25 of 'P' in 50 g of water lowers freezing point by 0.3°0. Molar mass of 'P' is 94. Kf(water) = 1.86 K kg mol-1. The degree of association of 'P' in water is
80%
60%
65%
75%
Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10-23 cm3. The smallest Cs-Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly
4.4 Å
4.3 Å
4 Å
4.5 Å
C.
4 Å
Volume, V = 7.014 × 10-23 cm3
a = 7.014 × 10-23 cm3
= 4.12 Å ≈ 4 Å