﻿ How many real solutions does the equation x7+ 14x5+ 16x3+ 30x – 560 = 0 have? from Mathematics Class 12 JEE Year 2008 Free Solved Previous Year Papers

### Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.

### Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

### Test Series

Pre-Board Question Papers are now available online for students to practice and excel the exams based on the latest syllabus and marking scheme given by respective boards.

# JEE Mathematics 2008 Exam Questions

#### Multiple Choice Questions

31.

The area of the plane region bounded by the curves x + 2y2= 0 and x + 3y2= 1 is equal to

• 5/3

• 1/3

• 2/3

• 4/3

D.

4/3

Solving the equations we get the points of intersection (–2, 1) and (–2,  1)The bounded region is shown as shaded region

163 Views

32.

How many real solutions does the equation x7+ 14x5+ 16x3+ 30x – 560 = 0 have?

• 7

• 1

• 3

• 5

B.

1

x7+ 14x5+ 16x3+ 30x – 560 = 0
Let f(x) = x7+ 14x5+ 16x3+ 30x
⇒ f′(x) = 7x6+ 70x4+ 48x2+ 30 > 0 ∀ x.
∴ f (x) is an increasing function ∀ x.

149 Views

33.

The value of

C.

98 Views

34.  then which one is true?
• I > 2/ 3 and J > 2

• I < 2/ 3 and J < 2

• I < 2/ 3 and J > 2

• I > 2/ 3 and J < 2

B.

I < 2/ 3 and J < 2

100 Views