Multiple Choice QuestionsGreen chemistry means such reactions which
produce colour during reactions
reduce the use and production of hazardous chemicals
are related to the depletion of the ozone layer
are related to the depletion of the ozone layer
B.
reduce the use and production of hazardous chemicals
Green chemistry involves such reactions which reduce the use and production of hazardous or toxic chemical to reduce pollution from the environment.
The value of KP1 and Kp2 for the reactions
X ⇌ Y +Z ... (i)
A ⇌ 2B ... (ii)
are in the ratio of 9:1. if the degree of dissociation of X and A be equal, then the total pressure at equilibrium (i) and (ii) are in the ratio
3:1
1:9
36:1
36:1
C.
36:1
From equation.
X ⇌ Y + Z
1 0 0 initial mole
(1-α) α α mole at equilibrium
On the basis of the following Eo values; the strongest oxidising agent is
[Fe(CN)6]4- → [Fe(CN)6]3-] +e- ;
Eo = -0.35 V
Fe2+ → Fe3+ +e-; E = -0.77 V
[Fe(CN)6]4-
Fe2+
Fe3+
Fe3+
C.
Fe3+
Oxidised form + ne- → Reduced Form
The substance which has lower reduction potential are stronger reducing agent while the substances which have higher reduction potential are a stronger oxidising agent.
[Fe(CN)6]3- + e- →[Fe(CN)6]4- ; Eo = 0.35 V
Fe3+ + e- → Fe2+ ; Eo = 0.77 V
The reduction potential of Fe3+/ Fe2+ is higher, hence, Fe3+ is a strongest oxidising agent.
The value of equilibrium constant of the reaction HI (g) ⇌ H2(g)/2 + I2/2 is 8.0
The equilibrium constant of the reaction H2(g) + I2(g) ⇌ 2 HI (g) will be
1/16
1/64
16
16
B.
1/64
HI (g) ⇌ H2/2(g) + I2/2(g)
The stability of carbanions in the following
is in the order of
(1) > (2) > (3) > (4)
(2) > (3) > (4) > (1)
(4) > (2) > (3) > (1)
(4) > (2) > (3) > (1)
A.
(1) > (2) > (3) > (4)
When s character increases, then electrons becomes more closer to the nucleus and structure is of lower energy and is more stable.
The stability order of carbanions is as:
Volume occipied by one molecule of water (density = 1 g cm-3) is
9.0 x 10-23
6.023 x 10-23 cm3
3.0 x 10-23 cm3
3.0 x 10-23 cm3
C.
3.0 x 10-23 cm3
6.02 x 1023 molecules of water = 1 mol
= 18 g
Therefore, Mass of one molecule of water
The alkali metals form salt-like hydrides by the direct synthesis at elevated temperature. The thermal stability of these hydrieds decreases in which of the following orders?
CsH > RbH > KH > NaH >LiH
KH > NaH> LiH > CsH >RbH
NaH > LiH >KH> RbH> CsH
NaH > LiH >KH> RbH> CsH
D.
NaH > LiH >KH> RbH> CsH
Small anion forms stable compounds with small cation.
The thermal stability of alkali metal hydrides decreases as:
LiH> NaH > KH > RbH >CsH
because the size of cation increases as;
Li+ < Na+ < K+ < Rb+ <Cs+
Which of the following complexes exhibits the highest paramagnetic behaviour?
Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities
(At. no. ; Ti = 22, V = 23, Fe =26, Co = 27)
[V(gly)2 (OH)2 (NH3)2]+
[Fe(en)(bpy)(NH3)2]+
[CO(OX)2(OH)2]-
[CO(OX)2(OH)2]-
C.
[CO(OX)2(OH)2]-
Greater is the number of unpaired electrons, larger is the paramagnetism.
[V(gly)2(OH)2(NH3)2]+
V23 = [Ar] 4s2, 3d2
Oxidation state of V in [[V(gly)2(OH)2(NH3)2]+ is
x + (-1) x 2 + (-1) x 2 + (0) x 2 = +1
x=+5
V5+ = [Ar]3d0
[Fe(en)(bby)(NH3)2]2+
x + (0) + (0) + (0) x 2 = +2
x = +2
Kohlrausch's law states that at
finite dilution, each ion makes a definite contribution to the equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
infinite dilution, each ion makes a definite contribution to the equivalent conductance of an electrolyte depending on the nature of the other ion of the electrolyte.
infinite dilution, each ion makes a definite contribution to the conductance of an electrolyte whatever be the nature of the other ions of the electrolyte.
infinite dilution, each ion makes a definite contribution to the conductance of an electrolyte whatever be the nature of the other ions of the electrolyte.
D.
infinite dilution, each ion makes a definite contribution to the conductance of an electrolyte whatever be the nature of the other ions of the electrolyte.
According to Kohlrausch's law "at infinite dilution when the dissociation is complete, each ion makes a definite contribution towards equivalent condctivity of the electrolyte irrespective of the nature of the order ion with which it is associated.
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