ï»¿ A uniform string of length 20 m is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is: (take g = 10 msâˆ’2 ) from Physics Gravitation Class 11 Manipur Board

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A uniform string of length 20 m is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is: (take g = 10 msâˆ’2 )

• 2s

C.

A uniform string of length 20 m is suspended from a rigid support. Such that the timeÂ takenÂ to reach the support.

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A uniform string of length 20 m is suspended from a rigid support. Such that the timeÂ takenÂ to reach the support.

Â

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The position co-ordinates of two particles of masses m1Â and m2are (x1, y1, z1) and (x2, y2, z2) respectively. Find the coordinates of the centre of mass.

The position vectors of masses m1Â and m2Â are respectively,

Let the position coordinates of the centre of mass be (X, Y, Z).

Therefore the position vector of centre of mass is,

Since, Â  Â

Â

Comparing the coefficients of Â , we get

Â

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