Solve 3ex tan y dx + (1 + ex) sec2 y dy = 0.  from Mathemati

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 Multiple Choice QuestionsShort Answer Type

121. Find a one parameter family of solutions of each of the following differential equation:
 (x y2 + 2x) dx + (x2 y + 2y) dy = 0
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122. Find a one parameter family of solutions of each of the following differential equation:
x y y' = 1 + x + y + x y
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123.

Solve:
dy over dx equals straight e to the power of straight x minus straight y end exponent plus straight x squared straight e to the power of straight y

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124.

Solve:
dy over dx space equals straight e to the power of straight x plus straight y end exponent plus straight x squared space straight e to the power of straight y.

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125.

Solve:
dy over dx space equals straight e to the power of straight x minus straight y end exponent plus straight x cubed straight e to the power of negative straight y end exponent

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126.

Solve:
x (1 + y2) dx + y (1 + x2)dy = 0  

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127.

Solve:
(1 + x) (1 + y2) dx + (1 + y) (1 + x2) dy = 0.

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128.

For the following differential equation, find the general solution:
dy over dx equals fraction numerator 1 minus cosx over denominator 1 plus cosx end fraction

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129.

For the following differential equation, find the general solution:
dy over dx space equals sin to the power of negative 1 end exponent straight x

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130. Solve 3ex tan y dx + (1 + ex) sec2 y dy = 0. 


The given differential equation is
                   3ex tan y dx + (1 + ex) sec2 y dy = 0
     or       left parenthesis 1 plus straight e to the power of straight x right parenthesis space sec squared straight y space dy space equals space minus space 3 space straight e to the power of straight x space tan space straight y space dx
or            fraction numerator sec squared straight y over denominator tan space straight y end fraction dy space equals space minus 3 fraction numerator straight e to the power of straight x over denominator 1 plus straight e to the power of straight x end fraction dx
Integrating, 
                            integral fraction numerator sec squared straight y over denominator tan space straight y end fraction dy space equals space minus 3 space integral fraction numerator straight e to the power of straight x over denominator 1 plus straight e to the power of straight x end fraction dx
therefore space space space space log space open vertical bar tan space straight y close vertical bar space equals space minus 3 space log space left parenthesis 1 plus straight e to the power of straight x right parenthesis space plus space straight c comma which is required solution..
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