xy = C
A homogeneous differential equation of the from   can be solved by making the substitution.Â
x = vy
x = vy
(4x + 6y + 5) dy – (3y + 2x + 4) dx = 0
(xy) dx – (x3 + y3) dy = 0
(x3Â + 2 y2) dx + 2xy dy = 0
(x3Â + 2 y2) dx + 2xy dy = 0