∫exx - 1x2dx is equal to from Mathematics Int

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 Multiple Choice QuestionsMultiple Choice Questions

641.

The value of π4π2exlogsinx + cotxdx is

  • eπ4log2

  • - eπ4log2

  • 12eπ4log2

  • - 12eπ4log2


642.

Considering four sub-intervals, the value of 0111 +xdx by Trapezoidal rule, is

  • 0.6870

  • 0.6677

  • 0.6977

  • 0.5970


643.

By Simpson's rule, the value of 12dxx dividing the interval (1, 2) into four equal parts, is

  • 0.6932

  • 0.6753

  • 0.6692

  • 7.1324


644.

The value of xsinxsec3xdx is

  • 12sec2x - tanx + c

  • 12xsec2x - tanx + c

  • 12xsec2x + tanx + c

  • 12sec2x + tanx + c


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645.

The value of 0xxsin3xdx is

  • 4π3

  • 2π3

  • 0

  • None of these


646.

Which of the following is true ?

  • 01exdx = e

  • 012xdx = log2

  • 01xdx = 23

  • 01xdx = 13


647.

sinlogx + coslogxdx is equal to

  • xcoslogx + c

  • coslogx + c

  • xsinlogx + c

  • sinlogx +c


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648.

exx - 1x2dx is equal to

  • exx2 + c

  • - exx2 + c

  • exx + c

  • - exx + c


C.

exx + c

exx - 1x2dx= ex1x - 1x2dx= exx + c  exfx + f'xdx = exfx + c


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649.

5101x - 1x - 2dx

  • log2732

  • log3227

  • log89

  • log34


650.

xlogxdx is equal to

  • x242logx - 1 + c

  • x222logx - 1

  • x242logx + 1 + c

  • x222logx + 1


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