Show that the lines: intersect. Find the point of intersection

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 Multiple Choice QuestionsLong Answer Type

281. Find the vector and cartesian equation of the plane containing the two lines
                straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space plus space straight j with hat on top space minus space 3 space straight k with hat on top space plus space straight lambda space left parenthesis straight i with hat on top space plus space 2 space straight j with hat on top space plus space 5 space straight k with hat on top right parenthesis
and    straight r with rightwards arrow on top space equals space 3 space straight i with hat on top space plus space space 3 space straight j with hat on top space minus space 7 space straight k with hat on top space plus space straight mu space left parenthesis 3 straight i with hat on top space minus space 2 space straight j with hat on top space plus space space 5 space straight k with hat on top right parenthesis

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 Multiple Choice QuestionsShort Answer Type

282. Find the equation of the plane containing the lines:
         fraction numerator straight x minus 4 over denominator 1 end fraction space equals space fraction numerator straight y minus 3 over denominator 4 end fraction space equals space fraction numerator straight z minus 2 over denominator 5 end fraction
and    fraction numerator straight x minus 3 over denominator 1 end fraction space equals space fraction numerator straight y minus 2 over denominator negative 4 end fraction space equals space straight z over 5

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 Multiple Choice QuestionsLong Answer Type

283. Find the equation of the plane passing through the points (3, 2, 1) and (0, 1, 7) and parallel to the line straight r with rightwards arrow on top space equals space 2 space straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top space plus space straight lambda left parenthesis straight i with hat on top space minus space straight j with hat on top space minus space straight k with hat on top right parenthesis.
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284. Find the equation of the plane passing through the points (1, 2, 3) and (0. –1, 0) and parallel to the line fraction numerator straight x minus 1 over denominator 2 end fraction space equals space fraction numerator straight y plus 2 over denominator 3 end fraction space equals space fraction numerator straight z over denominator negative 3 end fraction.
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285. Find the equation of the plane passing through the points (3, 2, 2) and (1, 0, –1) parallel to the line fraction numerator straight x minus 1 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator negative 2 end fraction space equals fraction numerator straight z minus 2 over denominator 3 end fraction.
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286. Find the equation of the plane passing through the origin and parallel to the vectors straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top space space space and space space 3 space straight i with hat on top space minus space straight k with hat on top.
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 Multiple Choice QuestionsShort Answer Type

287. Find the vector and Cartesian form of the equation of the plane passing through the point (1, 2, –4) and parallel to the lines
             straight r with rightwards arrow on top space equals straight i with hat on top space plus space 2 space straight j with hat on top space minus space 4 space straight k with hat on top space plus space straight lambda open parentheses 2 straight i with hat on top space plus space 3 space straight j with hat on top space plus space 6 space straight k with hat on top close parentheses
and       straight r with rightwards arrow on top space equals space straight i with hat on top space minus space 3 space straight j with hat on top space plus space space 5 space straight k with hat on top space plus space straight mu space open parentheses straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top close parentheses

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 Multiple Choice QuestionsLong Answer Type

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288. Show that the lines:
fraction numerator straight x minus 1 over denominator 2 end fraction space equals fraction numerator straight y minus 2 over denominator 3 end fraction space equals space fraction numerator straight z minus 3 over denominator 4 end fraction space and space fraction numerator straight x minus 4 over denominator 5 end fraction space equals space fraction numerator straight y minus 1 over denominator 2 end fraction space equals straight z intersect. Find the point of intersection also. 


The equations of lines are
                   fraction numerator straight x minus 1 over denominator 2 end fraction space equals space fraction numerator straight y minus 2 over denominator 3 end fraction space equals fraction numerator straight z minus 3 over denominator 4 end fraction                                             ...(1)

and           fraction numerator straight x minus 4 over denominator 5 end fraction equals space fraction numerator straight y minus 1 over denominator 2 end fraction space equals space fraction numerator straight z minus 0 over denominator 1 end fraction                                                ...(2)

Any point on line (1) is (2r + 1, 3r + 2, 4r + 3)

It lies on the line (2), if  fraction numerator 2 straight r plus 1 minus 4 over denominator 5 end fraction space equals fraction numerator 3 straight r plus 2 minus 1 over denominator 2 end fraction space equals fraction numerator 4 straight r plus 3 over denominator 1 end fraction

i.e.,  if   fraction numerator 2 straight r minus 3 over denominator 5 end fraction space equals space fraction numerator 3 straight r plus 1 over denominator 2 end fraction space equals space fraction numerator 4 straight r plus 3 over denominator 1 end fraction                                          ...(3)

Taking fraction numerator 2 straight r minus 3 over denominator 5 end fraction space equals space fraction numerator 3 straight r plus 1 over denominator 2 end fraction comma space space we space get comma
                  15 straight r plus 5 space equals space 4 straight r minus 6 comma space space space space space space space space space space space space space space space space space space space therefore space space space space 11 straight r space equals space minus 11 space space space rightwards double arrow space space space straight r space equals space minus 1
Substituting this value of r in (3), we get.
                   fraction numerator negative 2 minus 3 over denominator 5 end fraction space equals space fraction numerator negative 3 plus 1 over denominator 2 end fraction space equals space fraction numerator negative 4 plus 3 over denominator 1 end fraction
or               negative 1 space equals space minus 1 space space equals space minus 1 comma space space space which space is space true. space
∴  the lines intersect and the point of intersection is
(–2 + 1, –3 + 2, –4 + 3), i.e. (–1, –1, –1).


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289. Show that the lines fraction numerator straight x plus 3 over denominator negative 3 end fraction space equals space fraction numerator straight y minus 1 over denominator 1 end fraction space equals space fraction numerator straight z minus 5 over denominator 5 end fraction space and space fraction numerator straight x plus 1 over denominator negative 1 end fraction space equals fraction numerator straight y minus 2 over denominator 2 end fraction space equals fraction numerator straight z minus 5 over denominator 5 end fraction are coplanar.
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290. Show that the lines fraction numerator straight x minus 5 over denominator 4 end fraction space equals space fraction numerator straight y minus 7 over denominator 4 end fraction space equals space fraction numerator straight z plus 3 over denominator negative 5 end fraction and fraction numerator straight x minus 8 over denominator 7 end fraction space equals space fraction numerator straight y minus 4 over denominator 1 end fraction space equals space fraction numerator straight z minus 5 over denominator 3 end fraction intersect each other. 
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