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 Multiple Choice QuestionsMultiple Choice Questions

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1.

The materials suitable for making electromagnets should have

  • high retentivity and high coercivity

  • low retentivity and low coercivity

  • high retentivity and low coercivity

  • high retentivity and low coercivity


B.

low retentivity and low coercivity

Electromagnets are made of soft iron. The soft iron has high retentivity and low coercivity.

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2.

Two short bar magnets of length 1 cm each have magnetic moments 1.20 Am2 and 1.00 Am2 respectively. They are placed on a horizontal table parallel to each other with their N poles pointing towards the South.
They have a common magnetic equator and are separated by a distance of 20.0 cm. The value of the resultant horizontal magnetic induction at the mid - point O of the line joining their centres is close to(Horizontal component of earth’s magnetic induction is 3.6 × 10–5 Wb/m2)

  • 3.6 x10-5 Wb/m2

  • 2.56 x10-4 Wb/m2

  • 3.50  x10-4 Wb/m2

  • 3.50  x10-4 Wb/m2


B.

2.56 x10-4 Wb/m2

straight B subscript net space equals space straight B subscript straight M subscript 1 end subscript space plus straight B subscript straight M subscript 2 end subscript plus straight B subscript straight H
space equals fraction numerator straight mu subscript 0 straight M subscript 1 over denominator 4 πx cubed end fraction space plus fraction numerator straight mu subscript 0 straight M subscript 2 over denominator 4 πx cubed end fraction space plus straight B subscript straight H
space equals space fraction numerator straight mu subscript straight o over denominator 4 πx cubed end fraction left parenthesis straight M subscript 1 plus straight M subscript 2 right parenthesis space plus space straight B subscript straight H
space equals 10 to the power of negative 7 end exponent over 10 to the power of negative 3 end exponent straight x 2.2 space plus 3.6 space straight X 10 to the power of negative 5 end exponent
equals 2.56 space straight X 10 to the power of negative 4 end exponent space Wb divided by straight m squared
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3.

Relative permittivity and permeability of a material are εr and µr, respectively. Which of the following values of these quantities are allowed for a diamagnetic material?

  • εr = 0.5, µr = 1.5

  • εr = 1.5, µr = 0.5

  • εr = 0.5, µr = 0.5

  • εr = 0.5, µr = 0.5


B.

εr = 1.5, µr = 0.5

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4.

Two long conductors, separated by a distance d carry current I1 and I2 in the same direction. They exert a force F on each other. Now the current in one of them increased to two times and its direction reversed. The distance is also increased to 3d. The new value of the force between them is

  • −2F 

  • F/3

  • −2F/3

  • −2F/3


C.

−2F/3

Force acting between two current carrying conductors

straight F space equals space fraction numerator straight mu subscript 0 over denominator 2 straight pi end fraction fraction numerator straight I subscript 1 straight I subscript 2 over denominator straight d end fraction straight I space....... space left parenthesis straight i right parenthesis

where d = distance between the conductors,
          l = length of each conductor

straight F apostrophe space equals space fraction numerator straight mu subscript 0 over denominator 2 straight pi end fraction space fraction numerator left parenthesis negative 2 straight I subscript 1 right parenthesis left parenthesis straight I subscript 2 right parenthesis over denominator left parenthesis 3 straight d right parenthesis end fraction. space straight I
space equals space minus space fraction numerator straight mu subscript 0 over denominator 2 straight pi end fraction space fraction numerator left parenthesis negative 2 straight I subscript 1 right parenthesis left parenthesis straight I subscript 2 right parenthesis over denominator left parenthesis 3 straight d right parenthesis end fraction. straight I
space equals space minus space fraction numerator straight mu subscript 0 over denominator 2 straight pi end fraction fraction numerator 2 straight I subscript 1 straight I subscript 2 over denominator 3 straight d end fraction. space straight I space..... space left parenthesis ii right parenthesis
space thus comma space from space equations space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis space
fraction numerator straight F apostrophe over denominator straight F end fraction space equals space minus space 2 over 3
straight F apostrophe space equals space minus 2 straight F divided by 3

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5.

Needles N1, N2 and N3 are made of a ferromagnetic, a paramagnetic and a diamagnetic substance respectively. A magnet when brought close to them will

  • attract all three of them

  • attract N1 and N2 strongly but repel N3

  • attract N1 strongly, N2 weakly and repel N3 weakly

  • attract N1 strongly, N2 weakly and repel N3 weakly


C.

attract N1 strongly, N2 weakly and repel N3 weakly

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6.

The length of a magnet is large compared to its width and breadth. The time period of its width and breadth. The time period of its oscillation in a vibration magnetometer is 2 s. The magnet is cut along its length into three equal parts and three parts are then placed on each other with their like poles together. The time period of this combination will be

  • 2 s

  • 2/3 s

  • 2√3 s

  • 2√3 s


B.

2/3 s

The time period of oscillations of magnet
straight T space equals space 2 space straight pi square root of open parentheses 1 over MH close parentheses end root space...... space left parenthesis straight i right parenthesis
where I = moment of inertia of magnet = mL2/12  (m is being the mass of magnet)
M = pole strength × L When the three equal parts of magnet are placed on one another with their like poles together, then
straight I apostrophe space space equals space 1 over 12 open parentheses straight m over 3 close parentheses open parentheses straight L over 3 close parentheses squared space straight x space 3
space equals space 1 over 12 mL squared over 9
space equals space straight l over 9
and space straight M apostrophe space equals space pole space strength space straight x space straight L over 3 space straight x space 3
space equals space straight M
Hence comma space straight T apostrophe space equals space 2 straight pi square root of open parentheses fraction numerator straight I divided by 9 over denominator MH end fraction close parentheses end root
straight T apostrophe space equals space 1 third space straight x space straight T
straight T space equals space 2 divided by 3 space sec

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