The order of decreasing ease of abstraction of hydrogen atoms in the following molecule
Ha > Hb > Hc
Ha > Hc > Hb
Hb > Ha > Hc
Hc > Hb > Ha
B.
Ha > Hc > Hb
Abstraction of (Ha) hydrogen atom results in the formation of 3° allylic carbocation whereas abstraction of Hc gives 2° allylic carbocation (which is less stable as compared to former one).
However, abstraction of Hb gives only a 2° carbocation which is less stable as compared to former two. More the stability of generated carbocation, higher is the tendency of abstraction of hydrogen.
Thus, the order of decreasing ease of abstraction of hydrogen atoms from the given molecule is Ha > Hc > Hb.
Among the following statements about the molecules X and Y, the one(s) which correct is (are)
X and Y are diastereomers
X and Y are enantiomers
X and Y are both aldohexoses
X is a D-sugar and Y is an L-sugar
The electronic configuration of Cu is
[Ne] 3s2, 3p6, 3d9, 4s2
[Ne] 3s2, 3p6, 3d10, 4s1
[Ne] 3s2, 3p6, 3d3, 3d9, 4s2, 4p6
[Ne] 3s2, 3p6, 3d5, 4s2, 4p4
The rate of a certain reaction is given by, rate = k [H+]n. The rate increases 100 times when the pH changes from 3 to 1. The order (n) of the reaction is
2
0
1
1.5
The correct statement regarding the following energy diagrams is
Reaction M is faster and less exothermic than reaction N
Reaction M is slower and less exothermic than reaction N
Reaction M is faster and more exothermic than reaction N
Reaction M is slower and more exothermic than reaction N