Short Answer TypeArrange the following compounds in an increasing order of their solubility in water:
C6H5NH2, (C2H5)2NH, C2H5NH2The solubility order of the given amines is as follows:
C6H5NH2 < (C2H5)2NH < C2H5NH2
The more extensive the Hydrogen bonding, the higher is the solubility. C2H5NH2 contains two H-atoms whereas (C2H5)2NH contains only one H-atom. Thus, C2H5NH2undergoes more extensive. Hydrogen bonding than (C2H5)2NH. Hence, the solubility in water of C2H5NH2 is more than that of (C2H5)2NH.
Further, the solubility of amines decreases with increase in the molecular mass. This is because the molecular mass of amines increases with an increase in the size of the hydrophobic part.
The molecular mass of C6H5NH2 is greater than that of C2H5NH2 and (C2H5)2NH.
Explain the following giving one example for each:
(i) Reimer-Tiemann reaction.
(ii) Friedel Craft’s acetylation of anisole.
How would you obtain
(i) Picric acid (2, 4, 6-trinitrophenol) from phenol,
(ii) 2-Methylpropene from 2-methylpropanol?
What is essentially the difference between α-form of glucose and β-form of glucose? Explain.
Long Answer Type(a) Differentiate between molarity and molality for a solution. How does a change in temperature influence their values?
(b) Calculate the freezing point of an aqueous solution containing 10.50 g of MgBr2in 200 g of water. (Molar mass of MgBr2 = 184 g) (Kf for water = 1.86 K kg mol-1)
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