The solution of dydx + y tan(x) = sec(x) is : from Mathematics D

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 Multiple Choice QuestionsMultiple Choice Questions

501.

Let f : R  R be a differentiable function and f(1) = 4. Then the value of limx14fx2tx - 1dt, if f'(1) = 2 is :

  • 16

  • 8

  • 4

  • 2


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502.

The solution of dydx + y tan(x) = sec(x) is :

  • ysecx = tanx + c

  • ytanx = secx + c

  • tanx = ytanx + c

  • xsecx = tany + c


A.

ysecx = tanx + c

Given equation is,

dydx + ytanx = secxHere, P = tanx and Q = secx    IF = ePdx = etanxdx            = elogsecx = secx Solution is      y . secx = sec2xdx + c y . secx = tanx + c


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503.

The solution of dydx = ax + hby + k represents a parabola, when :

  • a = 0, b = 0

  • a = 1, b = 2

  • a = 0, b  0

  • a = 2, b = 1


504.

An integrating factor of the differential equation xdydx + ylogx = xexx12logx, (x > 0) is :

  • xlog(x)

  • xlogx

  • elogx2

  • ex2


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505.

The solution of edydx = x + 1, y(0) = 3 is :

  • y = xlog(x) - x + 2

  • y = (x + 1)logx + 1 - x + 3

  • y = x + 1logx + 1 + x + 3

  • y = xlogx + x + 3


506.

Solution of the differential equation dydxtany = sinx + y + sinx - y is :

  • secy + 2cosx = c

  • secy - 2cosx = c

  • cosy - 2sinx = c

  • tany - 2secy = c


507.

Solution of the differential equation dydx + yx = sinx is :

  • xy + cosx = sinx + c

  • xy - cosx = sinx + c

  • xycosx = sinx + c

  • xy - cosx = cosx + c


508.

The solution of the differential equation xdydx + 2y = x2 is :

  • y = x2 + c4x2

  • y = x24 + c

  • y = x2 + cx2

  • y = x4 + c4x2


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509.

y = - A cos(5x) + B sin(5x) satisfies the differential equation :

  • d2ydx2 + 10dydx + 25y = 0

  • d2ydx2 - 10dydx + 25y = 0

  • d2ydx2 - 25y = 0

  • d2ydx2 + 25y = 0


510.

The order and degree of the differential equation sinxdx + dy = cosxdx - dy is :

  • (1, 2)

  • (2, 2)

  • (1, 1)

  • (2, 1)


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