Let f : R R be a differentiable function and f(1) = 4. Then the value of , if f'(1) = 2 is :
16
8
4
2
The solution of represents a parabola, when :
a = 0, b = 0
a = 1, b = 2
a = 0, b 0
a = 2, b = 1
The solution of , y(0) = 3 is :
y = xlog(x) - x + 2
y = (x + 1)
y =
B.
y = (x + 1)