Let f : R R be a differentiable function and f(1) = 4. Then the value of , if f'(1) = 2 is :
16
8
4
2
The solution of represents a parabola, when :
a = 0, b = 0
a = 1, b = 2
a = 0, b 0
a = 2, b = 1
y = - A cos(5x) + B sin(5x) satisfies the differential equation :
D.